Electrical 5720

The bulb is connected to a 4.5 V power supply. An electric current of 45 mA flows through the filament of the bulb. The calculated size of the electrical field of the filament lamp

Correct answer:

R =  100 Ω

Step-by-step explanation:

$$\begin{gathered} U=4.5\text{V} \\ I=45/1000=\frac{9}{200}=0.045\text{A} \\ I=U/R \\ R=U/I=4.5/0.045=100\Omega \end{gathered}$$

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