Traveled journey

The tourist traveled 3/8 of the planned journey on the first day and 7/12 of the trip on the second day. On which day did he travel most of the way, and by how much?

Final Answer:

x = 2
y =  5/24

Step-by-step explanation:

$$\begin{gathered} a=\frac{3}{8}=0.375 \\ b=\frac{7}{12}\doteq 0.5833 \\ b>a \\ x=2 \end{gathered}$$

$y=b-a=\frac{7}{12}-\frac{3}{8}=\frac{14}{24}-\frac{9}{24}=\frac{14-9}{24}=\frac{5}{24}=0.2083$

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