Tourist

A tourist walked an average speed of 3.5 km/h route in 6 hours. Calculate how many hours he would have passed at an average speed of 5.5 km/h.

Result

t =  3.818 h

Solution:

v1=3.5 km/h t1=6 h v2=5.5 km/h  s=v1 t1=3.5 6=21 km  t=s/v2=21/5.542113.81823.818 hv_{1}=3.5 \ \text{km/h} \ \\ t_{1}=6 \ \text{h} \ \\ v_{2}=5.5 \ \text{km/h} \ \\ \ \\ s=v_{1} \cdot \ t_{1}=3.5 \cdot \ 6=21 \ \text{km} \ \\ \ \\ t=s/v_{2}=21/5.5 \doteq \dfrac{ 42 }{ 11 } \doteq 3.8182 \doteq 3.818 \ \text{h}



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