Tourist

A tourist walked an average speed of 3.5 km/h route in 6 hours. Calculate how many hours he would have passed at an average speed of 5.5 km/h.

Correct result:

t =  3.8182 h

Solution:

$$\begin{gathered} v_1=3.5\text{ km/h } \\ {t}_1=6\text{ h } \\ {v}_2=5.5\text{ km/h } \\ s=v_1\cdot t_1=3.5\cdot 6=21\text{ km } \\ t=s\mathrm{/}{v}_2=21\mathrm{/}5.5={\displaystyle \frac{42}{11}}=3.8182\text{ h} \end{gathered}$$

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