Three workers

A can do a work in 16 hours, and B alone in 24 hours. If A, B, and C work together and finish it in 8 hours, then C alone can finish it in how many hours?

Correct answer:

t3 =  48 h

Step-by-step explanation:

t1=16 h t2=24 h t=8 h  t (t11+t21+t31) = 1 t11+t21+t31= t1  t31 = t1t11t21 = s  s=t1t11t21=81161241=486483482=48632=4810.0208 1/h  t3=1/s=1/0.0208=48 h

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