Brick 5

A brick weighs 7/2 kg, a tile 11/8 kg. The first truck was carrying 900 bricks, the second truck was carrying 2000 tiles. Which car was carrying a heavier load and by how many kg.

Correct answer:

x =  1
o =  400 kg

Step-by-step explanation:

$$\begin{gathered} m_1=\frac{7}{2}=3.5\text{kg} \\ {m}_2=\frac{11}{8}=1.375\text{kg} \\ {n}_1=900 \\ {n}_2=2000 \\ {M}_1=n_1\cdot m_1=900\cdot \frac{7}{2}=\frac{900\cdot 7}{2}=\frac{6300}{2}=3150\text{kg} \\ {M}_2=n_2\cdot m_2=2000\cdot \frac{11}{8}=\frac{2000\cdot 11}{8}=\frac{22000}{8}=2750\text{kg} \\ {M}_1>M_2 \\ x=1 \end{gathered}$$

$o=M_1-M_2=3150-2750=400\text{kg}$

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