# Area codes

How many 6 digit area codes are possible if the first number can't be zero?

n =  900000

### Step-by-step explanation:

$n=9\cdot 1{0}^{6-1}=9\cdot 1{0}^{5}=900000$ Did you find an error or inaccuracy? Feel free to write us. Thank you! Tips to related online calculators
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