Dielectric change

An air capacitor with flat parallel plates has a capacitance of C₀ = 10 pF and a plate separation of d = 1 cm. A dielectric sheet of thickness Δ = 1 mm is inserted midway between the plates. What will be the capacitance of the device? (Edge effects may be neglected.)

Final Answer:

C2 =  11.1111 pF

Step-by-step explanation:

C0=10 pF d=1 cm mm=1 10  mm=10 mm Δ=1 mm  C0 = ε   dS C2 = ε   dΔS  ε S = C0 d C2 = dΔC0 d  C2=C0 dΔd=10 10110=11.1111 pF



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