Common work 2

Person A works twice as fast as person B. If both of them together can finish a piece of work in 12 days, how many days would person B alone take to do it?

Final Answer:

B =  36 d

Step-by-step explanation:

A = B/2   12 (A1+B1)=1 12 (B2+B1)=1 12 (B2+1)=1 12 B3=1  B=12 3=36=36 d   Verifying Solution:  A=B/2=36/2=18 s=A1+B1=181+361=362+361=362+1=363=1210.0833



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