# Trapezium

Determine the height of the trapezium ABCD, which has area 77.5 cm2 and base lengths 16 cm and 15 cm.

Result

h =  5 cm

#### Solution:

$S = \dfrac{a+c}{2} h \ \\ h = \dfrac{2S}{a+c} = \dfrac{ 2 \cdot 77.5 }{ 16+ 15 } = 5 \ \text{cm}$

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