Mailbox

Mailbox is opening at regular intervals 3 times a day. The first time is opened at 8:00 and the last at 19:00. Calculate hours when mailbox is opened during day.

Result

T1 = 8:00
T2 = 13:30
T3 = 19:00

Solution:

${T}_{1}=\left(1-1\right)\cdot \frac{19-8}{3-1}+8=8:00$
${T}_{2}=\left(2-1\right)\cdot \frac{19-8}{3-1}+8=13:30$
${T}_{3}=\left(3-1\right)\cdot \frac{19-8}{3-1}+8=19:00$

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