# Mailbox

Mailbox is opening at regular intervals 3 times a day. The first time is opened at 8:00 and the last at 19:00. Calculate hours when mailbox is opened during day.

Result

T1 = 8:00
T2 = 13:30
T3 = 19:00

#### Solution:

$T_1 = (1-1)\cdot \dfrac{ 19-8}{ 3-1} +8 = 8:00$
$T_2 = (2-1)\cdot \dfrac{ 19-8}{ 3-1} +8 = 13:30$
$T_3 = (3-1)\cdot \dfrac{ 19-8}{ 3-1} +8 = 19:00$

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