Mailbox

A mailbox is opened at regular intervals 5 times a day. It is first opened at 9:00 and last at 17:00. Calculate the times at which the mailbox is opened during the day.

Result

T₁ = 9:00
T₂ = 11:00
T₃ = 13:00
T₄ = 15:00
T₅ = 17:00

Step-by-step explanation:

$$\begin{gathered} h=\frac{17-9}{5-1}=2\text{h} \\ {T}_1=T_1=0\cdot h+9=0\cdot 2+9=9=9:00 \end{gathered}$$

$T_2=T_2=1\cdot h+9=1\cdot 2+9=11=11:00$

$T_3=T_3=2\cdot h+9=2\cdot 2+9=13=13:00$

$T_4=T_4=3\cdot h+9=3\cdot 2+9=15=15:00$

$T_5=T_5=4\cdot h+9=4\cdot 2+9=17=17:00$

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