# Enrollment

The enrollment at a local college increased 4% over last year's enrollment of 8548. Find the increase in enrollment (x1) and the current enrollment (x2).

Result

x1 =  341.9
x2 =  8889.9

#### Solution:

$x_1 = 8548\cdot \dfrac{ 4}{100} = 341.9$
$x_2 = 8548 + 8548\cdot \dfrac{ 4}{100} = 8889.9$

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