# Enrollment

The enrollment at a local college increased 4% over last year's enrollment of 8548. Find the increase in enrollment (x1) and the current enrollment (x2).

x1 =  341.9
x2 =  8889.9

### Step-by-step explanation:

${x}_{1}=8548\cdot \frac{4}{100}=341.9$
${x}_{2}=8548+8548\cdot \frac{4}{100}=8889.9$

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