n-gon II

What is the side length of the regular 5-gon circumscribed circle of radius 11 cm?

Correct answer:

x =  15.98 cm

Step-by-step explanation:

$$\begin{gathered} \theta ={\displaystyle \frac{180^{\circ }}{5}}={\displaystyle \frac{\pi }{5}}=36^{\circ } \\ x=2r\tan \theta =2r\tan ({\displaystyle \frac{\pi }{5}})=15.98\text{ cm} \end{gathered}$$

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