n-gon II

What is the side length of the regular 5-gon circumscribed circle of radius 11 cm?

Result

x =  15.98 cm

Solution:

θ=180∘5=π5=36∘ x=2rtan⁡θ=2rtan⁡(π5)=15.98 cm\theta = \dfrac{ 180 ^\circ }{ 5} = \dfrac{ \pi}{ 5} = 36 ^\circ \ \\ x = 2r \tan \theta = 2r \tan( \dfrac{ \pi}{ 5} ) = 15.98 \ \text{cm}

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