# n-gon

What is the side length of the regular 5-gon inscribed in a circle of radius 12 cm?

Result

x =  14.11 cm

#### Solution:

$\theta = \dfrac{ 180 ^\circ }{ 5} = \dfrac{ \pi}{ 5} = 36 ^\circ \ \\ x = 2r \sin( \dfrac{ \pi}{ 5} ) = 14.11 \ \text{ cm }$

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