Skier

At this point, the first skier lead 20 km before the second skier and travels at a constant speed 19 km/h. The second skier rides at 24 km/h.

How long take him to catch up the first?

Result

t =  4 h

Solution:

s=20 km Δv=2419=5 km/h t=sΔv t=205=4 hs = 20 \ km \ \\ \Delta v = 24 - 19 = 5 \ km/h \ \\ t = \dfrac{ s }{ \Delta v } \ \\ t = \dfrac{ 20 }{ 5 } = 4 \ \text{h}



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