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Between numbers 5 and 640, insert as many numbers as necessary to form a geometric progression, so the sum of the numbers you entered will be 630. How many numbers must you insert?

Final Answer:

m =  6

Step-by-step explanation:

a1=5 an = 640 sn  = 630+640+5 = 1275 an= a1 qn1 sn= a1 q1qn  1  128 = qn1 = qn/q 1275= a1 q1qn1  1275= 5 q1128 q  1 1275q  1275 = 5 (128 q  1) 635q = 1270 q=1270/635=2  128 = qn1  ln 128 = (n1) ln 2 n=ln2ln128+1=8  m=n2=82=6



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