The length of the rectangle is 8 smaller than three times the width. If we increase the width by 5% of the length and the length is reduced by 14% of the width, the circumference of rectangle will be increased by 30 m. What are the dimensions of the rectangle?


a =  4612 m
b =  1540 m


a = 3b-8
2(1.05a + (1-0.14)*b) = 30 + 2*(a+b)

a-3b = -8
0.1a-0.28b = 30

a = 4612
b = 1540

Calculated by our linear equations calculator.

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