# Tourist

A tourist walked an average speed of 3.5 km/h route in 6 hours. Calculate how many hours he would have passed at an average speed of 5.5 km/h.

Correct result:

t =  3.818 h

#### Solution:

$v_{1}=3.5 \ \text{km/h} \ \\ t_{1}=6 \ \text{h} \ \\ v_{2}=5.5 \ \text{km/h} \ \\ \ \\ s=v_{1} \cdot \ t_{1}=3.5 \cdot \ 6=21 \ \text{km} \ \\ \ \\ t=s/v_{2}=21/5.5=\dfrac{ 42 }{ 11 }=3.818 \ \text{h}$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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