In MATES (Small Television tipping) from 35 randomly numbers drawn 5 winning numbers. How many possible combinations there is?
Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):
Showing 0 comments:
Be the first to comment!
To solve this example are needed these knowledge from mathematics:
Next similar examples:
- Theorem prove
We want to prove the sentense: If the natural number n is divisible by six, then n is divisible by three. From what assumption we started?
Determine how many ways can be chosen two representatives from 34 students to school tournament.
How many different triads can be selected from the group 38 students?
The urn is 8 white and 6 black balls. We pull 4 randomly balls. What is the probability that among them will be two white?
- Fish tank
A fish tank at a pet store has 8 zebra fish. In how many different ways can George choose 2 zebra fish to buy?
- Calculation of CN
How many ways can divide 16 players into two teams of 8 member?
There are 9 interactive basic building blocks of an organization. How many two-blocks combinations are there?
The class is 21 students. How many ways can choose two to examination?
- The confectionery
The confectionery sold 5 kinds of ice cream. In how many ways can I buy 3 kinds if order of ice creams does not matter?
The village markets have 5 kinds of sweets, one weighs 31 grams. How many different ways a customer can buy 1.519 kg sweets.
8 girls wants to play volleyball against boys. On the field at one time can be six players per team. How many initial teams of this girls may trainer to choose?
How many 4-tones chords (chord = at the same time sounding different tones) is possible to play within 7 tones?
- Ice cream
Annie likes much ice cream. In the shop are six kinds of ice cream. In how many ways she can buy ice cream to three scoop if each have a different flavor mound and the order of scoops doesn't matter?
- Cancel fractions
Compress the expression of factorial: (n+6)!/(n+4)!-n!/(n-2)!
- Class pairs
In a class of 34 students, including 14 boys and 20 girls. How many couples (heterosexual, boy-girl) we can create? By what formula?
- Two equations
Solve equations (use adding and subtracting of linear equations): -4x+11y=5 6x-11y=-5