Round destiny

There are 5 white and 10 red balls in the destiny. 4 balls will be drawn at random. What is the probability of the event "at least 2 spheres are white"?

Correct answer:

p =  0.8352

Step-by-step explanation:

$$\begin{gathered} p_1=5\mathrm{/}15\cdot 10\mathrm{/}14\cdot 9\mathrm{/}13\cdot 8\mathrm{/}12={\displaystyle \frac{10}{91}}\doteq 0.1099 \\ {p}_2=5\mathrm{/}15\cdot 4\mathrm{/}14\cdot 10\mathrm{/}13\cdot 9\mathrm{/}12={\displaystyle \frac{5}{91}}\doteq 0.0549 \\ p=1-(p_1+p_2)=1-(0.1099+0.0549)={\displaystyle \frac{76}{91}}=0.8352 \end{gathered}$$

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