Round destiny

A bag contains 5 white and 10 red balls. Four balls are drawn at random. What is the probability of the event "at least two of the drawn balls are white"?

Final Answer:

p =  0.8352

Step-by-step explanation:

p1=5/15 10/14 9/13 8/12=91100.1099 p2=5/15 4/14 10/13 9/12=9150.0549 p=1(p1+p2)=1(0.1099+0.0549)=0.8352



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combinatoricsalgebraGrade of the word problem

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