Probability 68584

There are five whites and nine blacks in the destiny. We will choose three balls at random. What is the probability that
a) the selected balls will not be the same color,
b) will there be at least two blacks between them?

Correct answer:

p1 =  0.7418
p2 =  0.7253

Step-by-step explanation:

C3(14)=(314)=3!(143)!14!=321141312=364 C2(5)=(25)=2!(52)!5!=2154=10  C1(9)=(19)=1!(91)!9!=19=9  C1(5)=(15)=1!(51)!5!=15=5  C2(9)=(29)=2!(92)!9!=2198=36  p1=(35+9)(25) (19)+(15) (29)=(35+9)10 9+5 36=182135=0.7418
C0(5)=(05)=0!(50)!5!=11=1  C3(9)=(39)=3!(93)!9!=321987=84  p2=(35+9)(05) (39)+(15) (29)=(35+9)1 84+5 36=9166=0.7253

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