The urn is 8 white and 6 black balls. We pull 4 randomly balls. What is the probability that among them will be two white?

Correct result:

p =  0.4196


C4(14)=(144)=14!4!(144)!=141312114321=1001 C2(8)=(82)=8!2!(82)!=8721=28  C2(6)=(62)=6!2!(62)!=6521=15  p=(82) (62)(8+64)=28 15(8+64)=60143=0.4196

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