Conditional probability

Suppose a batch contains ten items, of which four are defective. Two items are drawn at random from the batch, one after the other, without replacement. What is the probability that:
I) both are defective?
Ii) Is the second item defective?

Correct answer:

p1 =  0.1333
p2 =  0.4

Step-by-step explanation:

r=104=52=0.4  p1=104 93=10 94 3=9012=152=0.1333
p2=104 93+106 94=52=0.4



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