The box

The box contains five chocolate, three fruit, and two menthol candies. We choose sweets at random from the box. What is the probability that we will take out one chocolate, one fruit, and one menthol candy without a return?

Correct result:

p =  4.1667 %

Solution:

$p=100\cdot {\displaystyle \frac{5}{5+3+2}}\cdot {\displaystyle \frac{3}{5+3+2-1}}\cdot {\displaystyle \frac{2}{5+3+2-2}}={\displaystyle \frac{25}{6}}=4.1667\mathrm{\%}$

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