# The tickets

The tickets to the show cost some integer number greater than 1. Also, the sum of the price of the children's and adult tickets, as well as their product, was the power of the prime number. Find all possible ticket prices.

Result

a1 =  2
a2 =  4
a3 =  8
a4 =  16

#### Solution:

$\ \\ a+b = p_{ 1 }^x \ \\ a \cdot \ b = p_{ 2 }^y \ \\ \ \\ p_{ 1 }, p_{ 2 } ... prime \ \\ n_{ 2 } = 2,4,6,8...., 2k \ \\ \ \\ a = b = p_{ 2 } \ \\ \ \\ a+b = 2 \ p_{ 2 } = p_{ 1 }^x \ \\ = > p_{ 1 } = 2 \ \\ p_{ 1 } \cdot \ p_{ 2 } = p_{ 1 }^x = 0 \ \\ \ \\ a_{ 1 } = 2 \ \\ b_{ 1 } = 2 \ \\ \ \\ s_{ 1 } = 2+2 = 4 = 2^2 \ \\ s_{ 2 } = 2 \cdot \ 2 = 4 = 2^2$
$a_{ 2 } = 4 \ \\ b_{ 2 } = 4 \ \\ \ \\ s_{ 1 } = 4+4 = 8 = 2^3 \ \\ s_{ 2 } = 4 \cdot \ 4 = 16 = 2^4$
$a_{ 3 } = 8 \ \\ b_{ 3 } = 8 \ \\ \ \\ s_{ 1 } = 8+8 = 16 = 2^4 \ \\ s_{ 2 } = 8 \cdot \ 8 = 64 = 2^6$
$a_{ 4 } = 16 \ \\ b_{ 4 } = 16 \ \\ \ \\ s_{ 1 } = 16+16 = 32 = 2^5 \ \\ s_{ 2 } = 16 \cdot \ 16 = 256 = 2^8$

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#### Following knowledge from mathematics are needed to solve this word math problem:

Do you want to calculate least common multiple two or more numbers? Do you want to calculate greatest common divisor two or more numbers?

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