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What is the perimeter of a right triangle with the legs 14 cm and 21 cm long?

Correct answer:

x =  60.24 cm

Step-by-step explanation:

$$\begin{gathered} c^2=a^2+b^2 \\ c=\sqrt{a^2+b^2}=\sqrt{14^2+21^2}=25.24cm \\ x=a+b+c=14+21+25.24=60.24\text{ cm} \end{gathered}$$

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