Isosceles trapezoid

What is the height of an isosceles trapezoid, the base of which has a length of 11 cm and 8 cm and whose legs measure 2.5 cm?

Result

h =  2 cm

Solution:

a=11 cm c=8 cm b=2.5 cm x=(a−c)/2=(11−8)/2=32=1.5 cm h=b2−x2=2.52−1.52=2=2  cm a = 11 \ cm \ \\ c = 8 \ cm \ \\ b = 2.5 \ cm \ \\ x = (a-c)/2 = (11-8)/2 = \dfrac{ 3 }{ 2 } = 1.5 \ cm \ \\ h = \sqrt{ b^2 - x^2 } = \sqrt{ 2.5^2 - 1.5^2 } = 2 = 2 \ \text{ cm }

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