Isosceles trapezoid

What is the height of an isosceles trapezoid, the base of which has a length of 11 cm and 8 cm and whose legs measure 2.5 cm?

Correct answer:

h =  2 cm

Step-by-step explanation:

$$\begin{gathered} a=11\text{ cm } \\ c=8\text{ cm } \\ b=2.5\text{ cm } \\ x=(a-c)\mathrm{/}2=(11-8)\mathrm{/}2={\displaystyle \frac{3}{2}}=1.5\text{ cm } \\ h=\sqrt{b^2-x^2}=\sqrt{2.5^2-1.5^2}=2\text{ cm} \end{gathered}$$

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