Shot

Shot with a mass 43 g flying at 256 m/s penetrates into the wood to a depth 25 cm.

What is the average force of resistance of wood?

Correct result:

F =  5636.1 N

Solution:

s=25 cm=0.25 m m=43 g=0.043 kg v=256 m/s  F=ma a=v/t s=12at2=12vt t=2hv=225/100256=0.001953 s a=v22h=2562225/100=131072 m/s2 F=ma=43/1000131072=5636.1 N



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