In center

What number lies in the center between a quarter of a fifth and a half of a third on the number axis?

Result

x =  0.108

Solution:

a=14⋅ 15=120=0.05 b=12⋅ 13=16≐0.1667  x=a+b2=0.05+0.16672=13120≐0.1083=0.108a = \dfrac{ 1 }{ 4 } \cdot \ \dfrac{ 1 }{ 5 } = \dfrac{ 1 }{ 20 } = 0.05 \ \\ b = \dfrac{ 1 }{ 2 } \cdot \ \dfrac{ 1 }{ 3 } = \dfrac{ 1 }{ 6 } \doteq 0.1667 \ \\ \ \\ x = \dfrac{ a+b }{ 2 } = \dfrac{ 0.05+0.1667 }{ 2 } = \dfrac{ 13 }{ 120 } \doteq 0.1083 = 0.108

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