Circumscribing 80498

Given is an acute-angled triangle ABC. On the half lines opposite to BA and CA lie successively the points D and E such that |BD| = |AC| and |CE| = |AB|. Prove that the center of the circle circumscribing triangle ADE lies on the circle circumscribing triangle ABC.

Correct answer:

x =  1

Step-by-step explanation:




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