# Chord

It is given to a circle k(r=6 cm) and the points A, B such that / AB / = 8 cm lies on k. Calculate the distance of the center of circle S to the midpoint C of the segment AB.

Result

x =  4.472 cm

#### Solution:

$r=6 \ \text{cm} \ \\ a=8 \ \text{cm} \ \\ a_{ 2 }=a/2=8/2=4 \ \text{cm} \ \\ x=\sqrt{ r^2-a_{ 2 }^2 }=\sqrt{ 6^2-4^2 } \doteq 2 \ \sqrt{ 5 } \doteq 4.4721 \doteq 4.472 \ \text{cm}$

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