# Fire tank

Whole fire tank was discharged once in 5 days by first out by second in \$n days. Once firefighters pumped out 6/13 of water out from the tank and then let the water flow out both drain.

How long take empty the tank?

Result

t =  1.01 d

#### Solution:

$t(\dfrac{1}{ 5} + \dfrac{1}{ 3}) = 1 - \dfrac{ 6 }{ 13} \ \\ \ \\ t = \dfrac{ 1 - \dfrac{ 6 }{ 13}}{ \dfrac{1}{ 5} + \dfrac{1}{ 3} } \ \\ t = 1.01 \ \text{ d }$

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