# Tram

In the three-part tram went 206 passengers in front of others, 226 after others and in the middle half.

How many passengers went in the tram total?

x =  288

## Step-by-step explanation:

a+b=206
b+c=226
b = 1/2·(a+b+c)
x=a+b+c

a+b = 206
b+c = 226
a-b+c = 0
a+b+c-x = 0

Row 3 - Row 1 → Row 3
a+b = 206
b+c = 226
-2b+c = -206
a+b+c-x = 0

Row 4 - Row 1 → Row 4
a+b = 206
b+c = 226
-2b+c = -206
c-x = -206

Pivot: Row 2 ↔ Row 3
a+b = 206
-2b+c = -206
b+c = 226
c-x = -206

Row 3 - 1/-2 · Row 2 → Row 3
a+b = 206
-2b+c = -206
1.5c = 123
c-x = -206

Row 4 - 1/1.5 · Row 3 → Row 4
a+b = 206
-2b+c = -206
1.5c = 123
-x = -288

x = -288/-1 = 288
c = 123/1.5 = 82
b = -206-c/-2 = -206-82/-2 = 144
a = 206-b = 206-144 = 62

a = 62
b = 144
c = 82
x = 288

Our linear equations calculator calculates it.

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
Do you have a system of equations and are looking for calculator system of linear equations?