# Folding table

The folding kitchen table has a rectangular shape with an area of 168dm2 (side and is 14 dm long). If necessary, it can be enlarged by sliding two semi-circular plates (at sides b). How much percent will the table area increase?
The result round to one-hundredths.

Result

p =  67.32 %

#### Solution:

$S = 168 \ dm^2 \ \\ a = 14 \ dm \ \\ \ \\ S = a \cdot \ b \ \\ \ \\ b = S/a = 168/14 = 12 \ dm \ \\ \ \\ r = b/2 = 12/2 = 6 \ dm \ \\ \ \\ S_{ 1 } = \pi \cdot \ r^2 = 3.1416 \cdot \ 6^2 \doteq 113.0973 \ dm^2 \ \\ \ \\ p = 100 \cdot \ \dfrac{ S_{ 1 } }{ S } = 100 \cdot \ \dfrac{ 113.0973 }{ 168 } \doteq 67.3198 = 67.32 \%$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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