Icerink

Rectangular rink with dimensions of 68.7 m and 561 dm must be covered with a layer of ice 4.2 cm thick. How many liters of water is necessary for the formation of ice when the volume of ice is 9.7% greater than the volume of water.

Result

V =  146169 l

Solution:

$x = 68.7 \ m = 68.7 \cdot \ 10 \ dm = 687 \ dm \ \\ y = 561 \ dm \ \\ z = 4.2 \ cm = 4.2 / 10 \ dm = 0.42 \ dm \ \\ \ \\ V_{ 1 } = x \cdot \ y \cdot \ z = 687 \cdot \ 561 \cdot \ 0.42 = 161870.94 \ l \ \\ q = 1 - \dfrac{ 9.7 }{ 100 } = \dfrac{ 903 }{ 1000 } = 0.903 \ \\ \ \\ V = V_{ 1 } \cdot \ q = 161870.94 \cdot \ 0.903 \doteq 146169.4588 = 146169 \ \text{ l }$

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