Ice and water

We want to cover rectangular rink with dimensions of 55 m and 25 m with 4cm thick layer of ice. How many liters of water we need if after freezing water increases its volume by 10%?

Correct answer:

V =  50000 l

Step-by-step explanation:

a=55 10=550 b=25 10=250 c=4/10=52=0.4 V1=a b c=550 250 0.4=55000 q=1+10/100=1011=1.1 V=V1/q=55000/1.1=50000 l



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