Ice and water

We want to cover rectangular rink with dimensions of 55 m and 25 m with 4cm thick layer of ice. How many liters of water we need if after freezing water increases its volume by 10%?

Result

V =  50000 l

Solution:

a=55⋅ 10=550 b=25⋅ 10=250 c=4/10=25=0.4 V1=a⋅ b⋅ c=550⋅ 250⋅ 0.4=55000 q=1+10/100=1110=1.1 V=V1/q=55000/1.1=50000 la=55 \cdot \ 10=550 \ \\ b=25 \cdot \ 10=250 \ \\ c=4/10=\dfrac{ 2 }{ 5 }=0.4 \ \\ V_{1}=a \cdot \ b \cdot \ c=550 \cdot \ 250 \cdot \ 0.4=55000 \ \\ q=1+10/100=\dfrac{ 11 }{ 10 }=1.1 \ \\ V=V_{1}/q=55000/1.1=50000 \ \text{l}

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