Ice and water

We want to cover rectangular rink with dimensions of 55 m and 25 m with 4cm thick layer of ice. How many liters of water we need if after freezing water increases its volume by 10%?

Correct result:

V =  50000 l

Solution:

$$\begin{gathered} a=55\cdot 10=550 \\ b=25\cdot 10=250 \\ c=4\mathrm{/}10={\displaystyle \frac{2}{5}}=0.4 \\ {V}_1=a\cdot b\cdot c=550\cdot 250\cdot 0.4=55000 \\ q=1+10\mathrm{/}100={\displaystyle \frac{11}{10}}=1.1 \\ V=V_1\mathrm{/}q=55000\mathrm{/}1.1=50000\text{ l} \end{gathered}$$

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