Ice and water

We want to cover a rectangular rink with dimensions of 55 m and 25 m with a 4cm thick layer of ice. How many liters of water do we need if freezing water increases its volume by 10%?

Correct answer:

V =  50000 l

Step-by-step explanation:

a=55 m dm=55 10  dm=550 dm b=25 m dm=25 10  dm=250 dm c=4 cm dm=4:10  dm=0.4 dm  V1=a b c=550 250 0.4=55000 dm3 1 l = 1 dm3  q=100%+10%=1+10010=1.1  V=V1/q=55000/1.1=50000 l

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