Sphere fall

How many percent fall volume of a sphere if diameter decreases 3×?

Correct answer:

p =  96.3 %

Step-by-step explanation:

V1=34πR3 V2=34πr3  R=3 r  V1=34π(3 r)3=34π33r3=33 V2  p=100 V1V1V2  p=100 33331=272600%=96.3%

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