Sphere fall

How many percent fall volume of a sphere if diameter decrease 3×?

Correct result:

p =  96.3 %

Solution:

V1=43πR3 V2=43πr3  R=3 r  V1=43π(3 r)3=43π33r3=33 V2  p=100 V1V2V1  p=100 33133=260027=96.3%



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