How many 9

How many percent volume remain of a sphere if diameter decrease 3×?

Correct result:

p =  96.2963 %

Solution:

d=D/3 r=R/3  V1=43πr3 V2=43πR3  p=100⋅ V1−V2V1  p=100⋅ R3−r3R3  p=100⋅ R3−(R/3)3R3  p=100⋅ 1−(1/3)31  p=100⋅ (1−(1/3)3)=260027=96.2963%

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