How many 9

How much percent volume remains of a sphere if the diameter decrease 3×?

Correct answer:

p =  96.2963 %

Step-by-step explanation:

d=D/3 r=R/3  V1=34πr3 V2=34πR3  p=100 V1V1V2  p=100 R3R3r3  p=100 R3R3(R/3)3  p=100 11(1/3)3  p=100 (1(1/3)3)=272600%=96.2963%



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