Two cars

Car A1 goes at average speed of 106 km/h and the second car A2 goes at 103 km/h. How many second will it take car A1 to circulate car A2? Assume that both cars are 5 meters long and the safety gap between cars is 1.5 meters.

Result

t =  15.6 s

Solution:

t=s/v s=2(5+1.5)=13 m v=(v1−v2)/3.6=(106−103)/3.6=0.833 m/s  t=13/0.833=15.6  s t = s/ v \ \\ s = 2(5+1.5) = 13 \ m \ \\ v = (v_1-v_2)/3.6 = (106-103)/3.6 = 0.833 \ m/s \ \\ \ \\ t = 13 / 0.833 = 15.6 \ \text{ s }

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