Rectangular garden

The perimeter of Peter's rectangular garden is 98 meters. The width of the garden is 60% shorter than its length.
Find the dimensions of the rectangular garden in meters.
Find the garden area in square meters.

Result

a =  35 m
b =  14 m
S =  490 m2

Solution:

o=98 m b=a−0.60a  o=2(a+b)   o=2⋅ (a+(a−0.60⋅ a))  98=2⋅ (a+(a−0.60⋅ a))  2.8a=98  a=35 =35 mo=98 \ \text{m} \ \\ b=a - 0.60a \ \\ \ \\ o=2(a+b) \ \\ \ \\ \ \\ o=2 \cdot \ (a+(a - 0.60 \cdot \ a)) \ \\ \ \\ 98=2 \cdot \ (a+(a - 0.60 \cdot \ a)) \ \\ \ \\ 2.8a=98 \ \\ \ \\ a=35 \ \\ =35 \ \text{m}
b=a−0.60a=35−0.60⋅ 35=14 mb=a - 0.60a=35 - 0.60 \cdot \ 35=14 \ \text{m}
S=a⋅ b=35⋅ 14=490 m2S=a \cdot \ b=35 \cdot \ 14=490 \ \text{m}^2

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