Rectangular garden

The perimeter of Peter's rectangular garden is 98 meters. The width of the garden is 60% shorter than its length.
Find the dimensions of the rectangular garden in meters.
Find the garden area in square meters.

Correct result:

a =  35 m
b =  14 m
S =  490 m²

Solution:

$$\begin{gathered} o=98\text{ m } \\ b=a-0.60a \\ o=2(a+b) \\ o=2\cdot (a+(a-0.60\cdot a)) \\ 98=2\cdot (a+(a-0.60\cdot a)) \\ 2.8a=98 \\ a=35=35\text{ m} \end{gathered}$$

$b=a-0.60a=35-0.60\cdot 35=14\text{ m}$

$S=a\cdot b=35\cdot 14=490{\text{m}}^2$

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