Basketball team

The heights of five starters on Redwood High's basketball team are 5'11", 6'3", 6'6", 6'2", and 6'. The average height of these players is?

Correct answer:

a = ft 6'2"

Step-by-step explanation:

$$\begin{gathered} h_1=5\cdot 12+11=71\text{inch} \\ {h}_2=6\cdot 12+3=75\text{inch} \\ {h}_3=6\cdot 12+6=78\text{inch} \\ {h}_4=6\cdot 12+2=74\text{inch} \\ {h}_5=6\cdot 12=72\text{inch} \\ b=\frac{h_1+h_2+h_3+h_4+h_5}{5}=\frac{71+75+78+74+72}{5}=74\text{inch} \\ 74=12\times 6+2 \\ a=6^{\prime }2" \end{gathered}$$

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