Basketball team

The heights of five starters on redwood high’s basketball team are 5’11”, 6’3”, 6’6”, 6’2” and 6’. The average of height of these players is?

Result

a = ft (Correct answer is: 6'2") Wrong answer

Solution:

h1=5⋅ 12+11=71 inch h2=6⋅ 12+3=75 inch h3=6⋅ 12+6=78 inch h4=6⋅ 12+2=74 inch h5=6⋅ 12=72 inch  b=h1+h2+h3+h4+h55=71+75+78+74+725=74 inch 74=12×6+2  a=6′2"h_{ 1 } = 5 \cdot \ 12+11 = 71 \ inch \ \\ h_{ 2 } = 6 \cdot \ 12+3 = 75 \ inch \ \\ h_{ 3 } = 6 \cdot \ 12+6 = 78 \ inch \ \\ h_{ 4 } = 6 \cdot \ 12+2 = 74 \ inch \ \\ h_{ 5 } = 6 \cdot \ 12 = 72 \ inch \ \\ \ \\ b = \dfrac{ h_{ 1 }+h_{ 2 }+h_{ 3 }+h_{ 4 }+h_{ 5 } }{ 5 } = \dfrac{ 71+75+78+74+72 }{ 5 } = 74 \ inch \ \\ 74 = 12 \times 6 + 2 \ \\ \ \\ a = 6'2"

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Showing 2 comments:
#
Dr Math
For conversion inches to feet and inch we user reminder calculator: https://www.hackmath.net/en/calculator/quotient-and-remainder?n=74&d=12 74 = 12 × 6 + 2 74 inch = 6 ft and 2 inch

#
Matematik

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