Players - baseball

There are 20 players on each of the two baseball teams. If 2/5 of the players on team 1 miss practice and 1/4 of the players on team 2 miss practice, how many more players from team 1 missed practice than team 2?

Final Answer:

x =  3

Step-by-step explanation:

$$\begin{gathered} t=20 \\ {m}_1=\frac{2}{5}\cdot t=\frac{2}{5}\cdot 20=\frac{2\cdot 20}{5}=\frac{40}{5}=8 \\ {m}_2=\frac{1}{4}\cdot t=\frac{1}{4}\cdot 20=\frac{1\cdot 20}{4}=\frac{20}{4}=5 \\ x=m_1-m_2=8-5=3 \end{gathered}$$

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