Find the 12

Find the equation of the circle with center (3,7) and circumference 8π units.

Result

e = (Correct answer is: e=pow(x-3, 2) +pow(y-7, 2) = 16) Wrong answer

Solution:

c=8π=8 3.141625.1327 r=c/(2π)=25.1327/(2 3.1416)=4  x0=3 y0=7  (xx0)2+(yy0)2=r2 e=(x3)2+(y7)2=16c = 8 \pi = 8 \cdot \ 3.1416 \doteq 25.1327 \ \\ r = c/(2 \pi) = 25.1327/(2 \cdot \ 3.1416) = 4 \ \\ \ \\ x_{ 0 } = 3 \ \\ y_{ 0 } = 7 \ \\ \ \\ (x-x_{ 0 })^2 +(y-y_{ 0 })^2 = r^2 \ \\ e = (x-3)^2 +(y-7)^2 = 16



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