Cylinder

The 1.8m cylinder contains 2000 liters of water. What area (in dm2) of this container is the water?

Result

S =  698.913 dm2

Solution:

D=1.8 m=1.8⋅ 10 dm=18 dm r=D/2=18/2=9 dm  V=2000 l=2000⋅ 1 dm3=2000 dm3  S1=π⋅ r2=3.1416⋅ 92≐254.469 dm2  h=V/S1=2000/254.469≐7.8595 dm  S=S1+π⋅ D⋅ h=254.469+3.1416⋅ 18⋅ 7.8595≐698.9134=698.913 dm2D = 1.8 \ m = 1.8 \cdot \ 10 \ dm = 18 \ dm \ \\ r = D/2 = 18/2 = 9 \ dm \ \\ \ \\ V = 2000 \ l = 2000 \cdot \ 1 \ dm^3 = 2000 \ dm^3 \ \\ \ \\ S_{ 1 } = \pi \cdot \ r^2 = 3.1416 \cdot \ 9^2 \doteq 254.469 \ dm^2 \ \\ \ \\ h = V/S_{ 1 } = 2000/254.469 \doteq 7.8595 \ dm \ \\ \ \\ S = S_{ 1 } + \pi \cdot \ D \cdot \ h = 254.469 + 3.1416 \cdot \ 18 \cdot \ 7.8595 \doteq 698.9134 = 698.913 \ dm^2

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