# When will I be a millionaire?

Barry monthly send 280 euros to the bank, which he deposits bear interest of 2.1% p. A. Calculate how many months must Barry save to save 1000000 euros?

Inflation, interest rate changes, or bank failures ignore.

Result

n =  1133 months

#### Solution:

$n = \lceil \dfrac { log( \dfrac{ 1000000 \cdot 2.1}{ 280 \cdot 100 \cdot 12} + 1)} { log(1+\dfrac{ 2.1}{100 \cdot 12})} \rceil = 1133 \ \text{ months }$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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