Water current

John swims upstream. After a while, he passes the bottle, and from that moment, he floats for 20 minutes in the same direction. He then turns around and swims back, and from the first meeting with the bottle, he sails 2 kilometers before he reaches the bottle. What is the current speed? (John is still swimming at the same speed regardless of the current.

Correct answer:

f =  3 km/h

Step-by-step explanation:

t1=20 min h=20:60  h=0.33333 h s=2 km  s1+s2=s s1=f t1 s2=f t2  s+(jf) t1=(j+f) t2  s+j t1f t1=j t2+f t2 s=f t1+f t2  s+j t1(sf t2)=j t2+f t2  s+j t1s+f t2=j t2+f t2 j t1=j t2 t2=t1=31=310.3333 h  f (t1+t2)=s  f=t1+t2s=31+t2s=0.3333+0.33332=3=3 km/h   Verifying Solution:  s1=f t1=f 31=3 0.3333=1 km s2=f t2=3 0.3333=1 km  j1=8 km/h  s3=(j1f) t1=(j1f) 31=(83) 0.3333=351.6667 km  t22=j1+fs+s3=j1+fs+35=8+32+1.6667=310.3333 h  t22=t2  j2=2 km/h  s4=(j2f) t1=(j2f) 31=(23) 0.3333=310.3333 km  t33=j2+fs+s4=j2+fs+31=2+32+(0.3333)=310.3333 h  t33=t2

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