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A liquid is heated at a rate of 5 degrees Celsius per minute. If the temperature now is at 39 degrees Celsius, how long will the temperature by 94 degrees Celsius?

Correct answer:

t =  11 min

Step-by-step explanation:

$$\begin{gathered} t_2=94^{\circ }\text{C } \\ {t}_1=39^{\circ }\text{C } \\ s=5^{\circ }\text{C/min } \\ t={\displaystyle \frac{94-39}{5}}=11\text{ min} \end{gathered}$$

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