Rate 3

A liquid is heated at a rate of 5 degrees Celsius per minute. If the temperature now is at 39 degrees Celsius, after how long will the temperature be 94 degrees Celsius?

Result

t =  11 min

Solution:

t2=94 ∘C t1=39 ∘C s=5 ∘C/min t=94−395=11 mint_{2}=94 \ ^\circ \text{C} \ \\ t_{1}=39 \ ^\circ \text{C} \ \\ s=5 \ ^\circ \text{C/min} \ \\ t=\dfrac{ 94-39 }{ 5 }=11 \ \text{min}

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