Coal

If the daily consumption of 1.6 tons of coal, it is sufficient to supply the boiler for 42 days. How long is sufficient to supply when will burn only 1.2 tons of coal a day ?

Result

t =  56 d

Solution:

t=42(1.6/1.2)=56 dt = 42\cdot (1.6/1.2) = 56 \ \text{d}



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