Coal storage

The coal storage distribute received coal shipment within three days. The first day distribute third of the shipments, the second day of two-fifths of the rest and the third day 300 tons of coal. How many tons of coal distributed first and second day?

Correct result:

a =  250 t
b =  200 t

Solution:

a+b+300 = t
a = t/3
b = 2/5(t - a)

a+b+300 = t
a = t/3
b = 2/5•(t - a)

a+b-t = -300
3a-t = 0
2a+5b-2t = 0

a = 250
b = 200
t = 750

Calculated by our linear equations calculator.
$b=200 \ \text{t}$

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