# Magnitude of angle

What magnitude has an obtuse angle enclosed by the hands of clocks at 12:20 hours?

Result

A =  250 °

#### Solution:

$F=360 \ ^\circ \ \\ \ \\ X=F \cdot \ (\dfrac{ 20 }{ 60 } - \dfrac{ 20 }{ 12 \cdot \ 60 } )=360 \cdot \ (\dfrac{ 20 }{ 60 } - \dfrac{ 20 }{ 12 \cdot \ 60 } )=110 \ ^\circ \ \\ \ \\ A=F - X=360 - 110=250=250 ^\circ$

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