Magnitude of angle

What magnitude has an obtuse angle enclosed by the hands of clocks at 12:20 hours?

Result

A =  250 °

Solution:

F=360 ∘  X=F⋅ (2060−2012⋅ 60)=360⋅ (2060−2012⋅ 60)=110 ∘  A=F−X=360−110=250=250∘F=360 \ ^\circ \ \\ \ \\ X=F \cdot \ (\dfrac{ 20 }{ 60 } - \dfrac{ 20 }{ 12 \cdot \ 60 } )=360 \cdot \ (\dfrac{ 20 }{ 60 } - \dfrac{ 20 }{ 12 \cdot \ 60 } )=110 \ ^\circ \ \\ \ \\ A=F - X=360 - 110=250=250 ^\circ

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