Magnitude of angle

What magnitude has an obtuse angle enclosed by the hands of clocks at 12:20 hours?

Correct answer:

A =  250 °

Step-by-step explanation:

$$\begin{gathered} F=360\text{ ° } \\ X=F\cdot ({\displaystyle \frac{20}{60}}-{\displaystyle \frac{20}{12\cdot 60}})=360\cdot ({\displaystyle \frac{20}{60}}-{\displaystyle \frac{20}{12\cdot 60}})=110\text{ ° } \\ A=F-X=360-110=250\text{°} \end{gathered}$$

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