Clock hands

Calculate the internal angles of a triangle whose vertices lie on the clock's 2, 6 and 11 hours.

Correct result:

A =  75 °
B =  60 °
C =  45 °

Solution:

φ=360/12=30∘ α=(6−2)⋅ φ=(6−2)⋅ 30=120∘ β=(11−6)⋅ φ=(11−6)⋅ 30=150∘ γ=(2+12−11)⋅ φ=(2+12−11)⋅ 30=90∘  A=β/2=150/2=75∘
B=α/2=120/2=60∘
C=γ/2=90/2=45∘

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