# Clock hands

Calculate the internal angles of a triangle whose vertices lie on the clock's 2, 6 and 11 hours.

Correct result:

A =  75 °
B =  60 °
C =  45 °

#### Solution:

$B=\alpha \mathrm{/}2=120\mathrm{/}2=6{0}^{\circ }$
$C=\gamma \mathrm{/}2=90\mathrm{/}2=4{5}^{\circ }$

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