Clock hands

Calculate the internal angles of a triangle whose vertices lie on the clock's 2, 6 and 11 hours.

Correct result:

A =  75 °
B =  60 °
C =  45 °

Solution:

φ=360/12=30 α=(62) φ=(62) 30=120 β=(116) φ=(116) 30=150 γ=(2+1211) φ=(2+1211) 30=90  A=β/2=150/2=75
B=α/2=120/2=60
C=γ/2=90/2=45



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